x^2+30x-125=0

Solution for x^2+30x-125=0 equation:

x^2+30x-125=0

a = 1; b = 30; c = -125;
Δ = b2-4ac
Δ = 302-4·1·(-125)
Δ = 1400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1400}=\sqrt{100*14}=\sqrt{100}*\sqrt{14}=10\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{14}}{2*1}=\frac{-30-10\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{14}}{2*1}=\frac{-30+10\sqrt{14}}{2}
$